Answer:
[tex]4n^{3} (3n^{2} + 4)[/tex]
Step-by-step explanation:
Assuming the problem is asking you to factor out the formula, it can be done easily by finding a common number with the two givens.
4 goes into both 12 and 16 evenly, so we will use this to factor. But that's not all, we have the n-variable to worry about.
Look at the n-variable exponents in the problem, take the highest power that can go be subtracted from both and use that. We have a [tex]n^{5}[/tex] and [tex]n^{3}[/tex]. Since 5 can't go into 3, we must use 3 to factor.
Our factoring variable will therefore be [tex]4n^{3}[/tex]. Now, use this to simply divide and get the answer:
[tex]( 12n^{5} + 16n^{3} ) / 4n^{3} = 4n^{3}(3n^{2} + 4)[/tex]
So how did we get this? For the whole numbers, we have to divide: (12/4, 16/4). Next, we have to minus the exponents since we are dividing.
When dividing the 12 and 4, minus the [tex]n^{5}[/tex] and [tex]n^{3}[/tex] to get [tex]n^{2}[/tex]. Get rid of the [tex]n^{3}[/tex] term for the 16 and leave the 4. And there's your answer!
