An observer standing on a cliff 320 feet above the measured angles of depression of the near and far sides of an island to be 16.5? and 10.5? respectively. How long is the island to the nearest foot?

Respuesta :

Answer: 94.72ft and 59.2ft


Step-by-step explanation:

Tan16.5=x/320

320tan16.5= 0.296

320(0.296)=94.72ft


Tan10.5=y/320

320tan10.5=0.185

320(0.185)=59.2ft


The length of the island to nearest foot is 2807 feet

Applications of Trigonometry

From the question, we are to determine the length of the island

Consider the diagram,

/DB/ is the height of the cliff

The length of the island is /AC/

First, we will calculate /AB/

Consider ΔABD

Using SOH CAH TOA

[tex]tan 16.5^\circ = \frac{/DB/}{/AB/}[/tex]

[tex]tan 16.5^\circ = \frac{320}{/AB/}[/tex]

[tex]0.2962= \frac{320}{/AB/}[/tex]

[tex]/AB/=\frac{320}{0.2962}[/tex]

/AB/ = 1080.35 feet

Now, we will calculate /BC/

Consider ΔDBC

[tex]tan 10.5^\circ = \frac{/DB/}{/BC/}[/tex]

[tex]tan 10.5^\circ = \frac{320}{/BC/}[/tex]

[tex]0.1853= \frac{320}{/BC/}[/tex]

[tex]/BC/=\frac{320}{0.1853}[/tex]

/BC/ = 1726.93 feet

In the diagram,

/AC/ = /AB/ + /BC/

/AC/ = 1080.35 feet + 1726.93 feet

/AC/ = 2807.28 feet

/AC/ ≅ 2807 feet

Hence, the length of the island to nearest foot is 2807 feet.

Learn more on Trigonometry here: https://brainly.com/question/17022372

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