[tex](fg)(x)=f(x)\cdot g(x)\\\\\text{We have}\ c(x)=\dfrac{5}{x-2}\ \text{and}\ d(x)=x+3.\ \text{Substitute}\\\\(cd)(x)=\dfrac{5}{x-2}\cdot(x+3)=\dfrac{5(x+3)}{x-2}\\\\\text{Domain:}\\\\\text{The denominator must be different than zero. Therefore}\\\\x-2\neq0\to x\neq2\\\\Answer:\ \text{Domain is the set of all real numbers except 2}\to D=\mathbb{R}-\{2\}[/tex]
