Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.

After adding B2 to both sides of the equation in step 4, what is the constant on the right side of the equation?

A. -32
B. 112
C. 160

Respuesta :

Answer:

constant = -12

Step-by-step explanation:

Let the given equation be

2x² + 8x - 12 = 0     --------(1)

Here B² =(2√2)^2 = 8

Add 8 in both sides  of (1)

Step1 :  2x² + 8x  + 4 = 12  + 4

Step 2:  x² + 4x + 4 = 16

step 3 : x² + 4x + 4 - 16 = 0

Step 4:  x² + 4x - 12 = 0  ---(4)

From the (4) we get constant = -12



Answer: 160

Explanation:

2x^2 + 8x - 12 = 0

a = 2 b = 8

Multiply both sides by 4a, or 8.

16x^2 + 64x - 96 = 0

Move the constant to the right side of equation.

16x^2 + 64x = 96

Add b^2 to both sides, or 64.  Then factor as a square of a binomial.  

16x^2 + 64x + 64 = 96 + 64

(4x + 8)^2 = 160

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