Answer with Step-by-step explanation:
We are given right angled triangles so using the Pythagoras Theorem to find the length of the unknown side for each triangle:
19. x=21.65
[tex]25^2=x^2+12.5^2[/tex]
[tex]\sqrt{x^2} =\sqrt{468.75}[/tex]
[tex]x^2=25^2-12.5^2[/tex]
[tex]x=21.65[/tex]
20. x = 8.06
[tex]9^2=x^2+4^2[/tex]
[tex]x^2=9^2-4^2[/tex]
[tex]\sqrt{x^2} =\sqrt{65}[/tex]
[tex]x=8.06[/tex]
21. x = 34.01
[tex]x=\sqrt{14^2+31^2}[/tex]
[tex]x=\sqrt{1157}[/tex]
[tex]x=34.01[/tex]
22. x = 13
[tex]x=\sqrt{5^2+12^2}[/tex]
[tex]x=\sqrt{169}[/tex]
[tex]x=13[/tex]
23. x = 6
[tex]10^2=x^2+8^2[/tex]
[tex]x^2=10^2-8^2[/tex]
[tex]\sqrt{x^2} =\sqrt{36}[/tex]
[tex]x=6[/tex]
24. x = 16
[tex]20^2=x^2+12^2[/tex]
[tex]x^2=20^2-12^2[/tex]
[tex]\sqrt{x^2} =\sqrt{256}[/tex]
[tex]x=16[/tex]
25. x = 60
[tex]65^2=x^2+25^2[/tex]
[tex]x^2=65^2-25^2[/tex]
[tex]\sqrt{x^2} =\sqrt{3600}[/tex]
[tex]x=60[/tex]
26. x = 32
[tex]40^2=x^2+24^2[/tex]
[tex]x^2=40^2-24^2[/tex]
[tex]\sqrt{x^2} =\sqrt{1024}[/tex]
[tex]x=32[/tex]
27. x = 14
[tex]50^2=x^2+48^2[/tex]
[tex]x^2=50^2-48^2[/tex]
[tex]\sqrt{x^2} =\sqrt{196}[/tex]
[tex]x=14[/tex]
