tetimenchon0604
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Janine has job offers from two companies. One company offers a starting salary of $28,000 with a raise of $3,000 each year. The other company offers a starting salary of $36,000 with a raise of $2,000 each year.

a. After how many years would Janine's salary be the same with both companies?
b. What would that salary be?

Respuesta :

mathecoach

Answer:

a)

28000 + 3000·x = 36000 + 2000·x --> x = 8 years

b)

28000 + 3000·8 = $52000

In 8 years, their salary will be $52000

a. Let the number of years be y

This will be represented as:

Company A = 28000 + (3000 × y)

= 28000 + 3000y

Company B = 36000 + (2000 × y)

= 36000 + 2000y

The equation will be:

28000 + 3000y = 36000 + 2000y

Collect like terms

3000y - 2000y = 36000 - 28000

1000y = 8000

y = 8000/1000

y = 8.

The number of years will be 8 years

b. The salary will be:

= 28000 + 3000y

= 28000 + 3000(8)

= 28000 + 24000

= 52000

The salary is $52000

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