Respuesta :
Answer:
Area of triangle DFG = 175
Area of triangle ABC = 252
Step-by-step explanation:
It is given that,
The triangles ABC and DFG are similar and the ratio of their corresponding sides is 6:5. The area of the triangle ABC is greater than the area of the triangle DFG by 77 cm2.
Let area of triangle DFG = x then area of triangle ABC = x + 77
To find the area of 2 triangles
ar(DFG)/ar(ABC = (5/6)²
x/(x + 77) = 25/36
36x = 25x + (25 * 77)
36x - 25x = 25 * 77
11x = 25 * 77
x = 175
Therefore area of triangle DFG = 175
Area of triangle ABC = 175 + 77 = 252
Similar triangles may or may not be congruent.
The areas of triangles ABC and DFG are 252 and 175 square centimeters, respectively.
The given parameters are:
[tex]\mathbf{\triangle ABC \sim \triangle DFG}[/tex] ---- similar triangles
[tex]\mathbf{ABC : DFG =6 : 5}[/tex] -- ratio of the sides
[tex]\mathbf{Area_{ABC} = Area_{DFG} + 77}[/tex] --- the areas
So, the relationship between the areas of the triangle is the square of the ratio of the side lengths.
i.e.
[tex]\mathbf{ABC : DFG =6^2 : 5^2}[/tex]
[tex]\mathbf{ABC : DFG =36 : 25}[/tex]
Express as fraction
[tex]\mathbf{\frac{ABC }{ DFG} =\frac{36 }{ 25}}[/tex]
Let triangle DFG represent x and triangle ABC represent y.
So, we have:
[tex]\mathbf{\frac{y }{ x} =\frac{36 }{ 25}}[/tex]
and
[tex]\mathbf{y = x + 77}[/tex]
[tex]\mathbf{\frac{y }{ x} =\frac{36 }{ 25}}[/tex] becomes
[tex]\mathbf{\frac{x + 77 }{ x} =\frac{36 }{ 25}}[/tex]
Cross multiply
[tex]\mathbf{25(x + 77) = 36x}[/tex]
Expand
[tex]\mathbf{25x + 1925 = 36x}[/tex]
Collect like terms
[tex]\mathbf{36x - 25x = 1925}[/tex]
[tex]\mathbf{11x = 1925}[/tex]
Divide
[tex]\mathbf{x = 175}[/tex]
Recall that:[tex]\mathbf{y = x + 77}[/tex]
So, we have:
[tex]\mathbf{y = 175 + 77}[/tex]
[tex]\mathbf{y = 252}[/tex]
Hence, the areas of triangles ABC and DFG are 252 and 175 square centimeters, respectively.
Read more about areas at:
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