The triangles ABC and DFG are similar and the ratio of their corresponding sides is 6:5. The area of the triangle ABC is greater than the area of the triangle DFG by 77 cm2. Find the areas of these triangles.

Respuesta :

Answer:

Area of triangle DFG = 175

Area of triangle ABC  = 252

Step-by-step explanation:

It is given that,

The triangles ABC and DFG are similar and the ratio of their corresponding sides is 6:5. The area of the triangle ABC is greater than the area of the triangle DFG by 77 cm2.

Let area of triangle DFG = x  then area of triangle ABC = x + 77

To find the area of 2 triangles

ar(DFG)/ar(ABC = (5/6)²

x/(x + 77) = 25/36

36x = 25x + (25 * 77)

36x - 25x = 25 * 77

11x = 25 * 77

x = 175

Therefore area of triangle DFG = 175

Area of triangle ABC = 175 + 77 = 252

Similar triangles may or may not be congruent.

The areas of triangles ABC and DFG are 252 and 175 square centimeters, respectively.

The given parameters are:

[tex]\mathbf{\triangle ABC \sim \triangle DFG}[/tex] ---- similar triangles

[tex]\mathbf{ABC : DFG =6 : 5}[/tex] -- ratio of the sides

[tex]\mathbf{Area_{ABC} = Area_{DFG} + 77}[/tex] --- the areas

So, the relationship between the areas of the triangle is the square of the ratio of the side lengths.

i.e.

[tex]\mathbf{ABC : DFG =6^2 : 5^2}[/tex]

[tex]\mathbf{ABC : DFG =36 : 25}[/tex]

Express as fraction

[tex]\mathbf{\frac{ABC }{ DFG} =\frac{36 }{ 25}}[/tex]

Let triangle DFG represent x and triangle ABC represent y.

So, we have:

[tex]\mathbf{\frac{y }{ x} =\frac{36 }{ 25}}[/tex]

and

[tex]\mathbf{y = x + 77}[/tex]

[tex]\mathbf{\frac{y }{ x} =\frac{36 }{ 25}}[/tex] becomes

[tex]\mathbf{\frac{x + 77 }{ x} =\frac{36 }{ 25}}[/tex]

Cross multiply

[tex]\mathbf{25(x + 77) = 36x}[/tex]

Expand

[tex]\mathbf{25x + 1925 = 36x}[/tex]

Collect like terms

[tex]\mathbf{36x - 25x = 1925}[/tex]

[tex]\mathbf{11x = 1925}[/tex]

Divide

[tex]\mathbf{x = 175}[/tex]

Recall that:[tex]\mathbf{y = x + 77}[/tex]

So, we have:

[tex]\mathbf{y = 175 + 77}[/tex]

[tex]\mathbf{y = 252}[/tex]

Hence, the areas of triangles ABC and DFG are 252 and 175 square centimeters, respectively.

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