Answer: [tex]\bold{B.\ \pm5\quad D.\ \pm1\quad E.\ \pm \dfrac{1}{3}}[/tex]
Step-by-step explanation:
Q P
F(x) = 3x² - 3x + 5
The possible rational roots are all of the factors of P divided by each of the factors of Q - including both positive and negative values.
[tex]\dfrac{P=5}{Q=3}=\pm \dfrac{1,5}{1,3}=\pm \bigg\{\dfrac{1}{1},\dfrac{1}{3},\dfrac{5}{1},\dfrac{5}{3}\bigg\}=\pm \bigg\{1, \dfrac{1}{3},5,\dfrac{5}{3}\bigg\}[/tex]
