The time taken on the trip to the rest area is 2 hours while that on the return trip is 2.25 hours or 2 hours and 15 minutes. The distance between the camp and the rest area of 9 miles.
Given:
The speed of campers on the way to the rest area is 4.5 mph.
The speed of campers on the way to the camp is 4 mph.
Let the time taken on the way to the rest area of t hours. The time on the way back will be t+0.25 hours. (15 minutes is 0.25 hours).
The distance d between the camp and the rest area will be the same for both the trips.
So, mathematically, it can be written as,
[tex]d=4.5\times t=4\times (t+0.25)\\0.5 t=1\\t=2\rm \; hours\\d=4.5t\\d=4.5\times 2\\d=9\rm\; miles[/tex]
Therefore, the time taken on the trip to the rest area is 2 hours while that on the return trip is 2.25 hours or 2 hours and 15 minutes. The distance between the camp and the rest area of 9 miles.
For more details, refer to the link:
https://brainly.com/question/23774048
