Factor by grouping.....
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Answer:
A. [tex](4x^{2}+1)(3x+1 )[/tex]
Step-by-step explanation:
The following lines will show the process of factorization by using common factor.
Line 1:
In line 1, we group terms from which the common terms will be factored out.
[tex]12x^{3}+4x^{2}+3x+1=0[/tex]
[tex](12x^{3}+4x^{2} )+(3x+1)=0[/tex]
Line 2:
In line 2, we find the common terms from both groups. [tex]4x^{2}[/tex] is the common term in group 1 and 1 is common for group 2.
[tex]4x^{2}(3x+1 )+1(3x+1)=0[/tex]
Now we take out the common term from whole equation which is 3x+1.This leaves us with equation as follows:
[tex](3x+1 )(4x^{2}+1)=0[/tex]
which is option A.
So option A. [tex](4x^{2}+1)(3x+1 )[/tex] is the correct answer.