Hello from MrBillDoesMath!
Answer:
See discussion below
Discussion:
A real brain teaser!
If f(x) = x^2 + 2x + 3, then
a. f(-x) = (-x)^2 + 2(-x) +3
= x^2 -2x + 3
b. - f(x) = - (x^2 + 2x + 3) = -x^2 -2x - 3
c. Using a) above
-f(-x) = - (x^2 -2x + 3 ) = -x^2 + 2x - 3
Note that f(x) is not an even function ( f(x) = f(-x) ) or an odd function ( f(-x) = - f(x))
Thank you,
MrB
