Answer:
it will take 0.35 s to move off
Explanation:
As we know that the ball rolls horizontally on a table of height 0.6 m
so here we can say that in vertical direction the motion is free fall under gravity
so we can say
[tex]y = \frac{1}{2}gt^2[/tex]
[tex]0.6 = \frac{1}{2}(9.8)t^2[/tex]
here we will have
[tex]0.6 = 4.9 t^2[/tex]
[tex]t = 0.35 s[/tex]
