√53 is the answer First you find the hypotenuse of the 4 by 1 rectangle on the front panel to see how long the first leg is. [tex]4 {}^{2} + 1 {}^{2} = \sqrt{17} [/tex] Now you use that and your other leg of 6 to find the length of your line [tex] \sqrt{17 {}^{2} } + 6 {}^{2} = \sqrt{53} [/tex]