Anna, Ivan and Elena are running for class president. On Thursday night Anna had 20% of the votes, Ivan had 35% of the votes and Elena had 45% of the votes. On Friday, final votes were added to the counts and all of them favored Elena. If in the end Anna had 16% of all votes, what percent of the voters chose Ivan?

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frika

Answer:

28%

Step-by-step explanation:

On Thursday night Anna had 20% of the votes, Ivan had 35% of the votes and Elena had 45% of the votes. You can take the number of total votes on Thursday equal to 100, then Anna had 20 votes, Ivan had 35 votes and Elena had 45 votes.

Let x be the number of votes added on Friday. All of them favored Elena, then Elena in total had 45+x votes and the number of all votes became 100+x. In the end Anna had 16%, then

100+x - 100%,

20 - 16%.

Write a proportion:

[tex]\dfrac{100+x}{20}=\dfrac{100}{16},\\ \\16(100+x)=2000,\\ \\1600+16x=2000,\\ \\16x=400,\\ \\x=25.[/tex]

Find the percent of the voters that chose Ivan:

125 - 100%,

35 - y%.

Write a proportion:

[tex]\dfrac{125}{35}=\dfrac{100}{y},\\ \\125y=35\cdot 100,\\ \\y=\dfrac{35\cdot 100}{125}=\dfrac{35\cdot 4}{5}=7\cdot 4=28\%.[/tex]

Answer:

I think it would be 28%

Step-by-step explanation:

I did this in rsm

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