One grain of sand approximately weighs 7 * 10^{-5} g. How many grains of sand are there in 6300 kg of sand? Give your answer in standard form.

Respuesta :

Answer:

Proportion states that the two ratio or fractions are equal.

Given the statement: One grain of sand approximately weighs 7 * 10^{-5} g.

To find how many grains of sand are there in 6300 kg of sand.

Let x be the number of grains of sand in 6300 kg of sand.

Using conversion :

1 kg = 1000 g

6300 kg = 6300000 g

Then, by using proportion method, we have;

[tex]\frac{1}{7\times 10^{-5}}= \frac{x}{6300000}[/tex]

[tex]\frac{10^5}{7} = \frac{x}{6300000}[/tex]

By cross multiply we get;

[tex]6300000 \times 10^5 = 7x[/tex]

or

[tex]63 \times 10^5 \times 10^5 = 7x[/tex]

[tex]63 \times 10^{5+5} = 7x[/tex]  [using [tex]x^a \cdot x^b = x^{a+b}[/tex]]

[tex]63 \times 10^{10} = 7x[/tex]

Divide both sides by 7 we get;

[tex]x = \frac{63 \times 10^{10}}{7} = 9 \times 10^{10}[/tex]

Standard form is a way of of writing down very large or very small numbers easily.

Therefore, [tex]9 \times 10^{10}[/tex] grains of sand are there in 6300 kg of sand.