contestada

A ball is thrown vertically upward from the top of a
building 96 feet tall with an initial velocity of 80 feet
per second. The distance, s (in feet), of the ball from
the ground after t seconds is given by the function:
() = 96 + 80 − 16
2

a. How long does it take for the ball to reach its
highest point?
b. What is the maximum height the ball reaches?

Respuesta :

Answer:

It takes 2.5 seconds for the ball to reach its  highest point

Maximum height is 196 feet

Step-by-step explanation:

h(t) = -16t^2+80t +96

a=-16, b= 80, c=96

To find the maximum height , we need to find vertex

Let find x coordinate of vertex

[tex]t=\frac{-b}{2a}[/tex]

Plug in the values

[tex]t=\frac{-80}{2(-16)}= 2.5[/tex]

It takes 2.5 seconds for the ball to reach its  highest point

Now plug in 2.5 for t to find maximum height

[tex]h(t) = -16t^2+80t +96[/tex]

[tex]h(2.5) = -16(2.5)^2+80(2.5) +96=196[/tex]

Maximum height is 196 feet

Otras preguntas