[tex]f(x)=-\frac{2}{3}x+5[/tex]
f(12) this means that x is 12, so you can plug in 12 for "x" in the function:
[tex]f(x)=-\frac{2}{3}x+5[/tex]
[tex]f(12)=-\frac{2}{3}(12)+5[/tex]
[tex]f(12)=-\frac{24}{3} +5[/tex]
f(12) = -8 + 5
f(12) = -3
Your answer is -3
