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Fe3+(aq) (yellow) + SCN-(aq) (colorless) FeSCN2+(aq) (blood-red) Chloride ions are colorless. Potassium ions are also colorless. The above equilibrium can be created by mixing an Iron (III) chloride solution with a potassium thiocyanate solution. Based on this information and the colors in the equilibrium above answer the first two questions. 1. What color would an FeCl3 solution be? 2. What color would a KSCN solution be? 3. What color do you get when you mix FeCl3 and KSCN as shown in the video for the control test tube?

Respuesta :

Explanation:

[tex]Fe^{3+}\text{(aq)(yellow)}+SCN^-\text{(aq)(colorless)}\rightleftharpoons FeSCN^{2+}\text{(aq)(blood-red)}[/tex]

[tex]K^+\text{(aq)(colorless)}+Cl^-\text{(aq)(colorless)}\rightarrow KCl[/tex]

The above two reactions xcan also be written in form of single chemcial equation:

[tex]FeCl_3+K(SCN)\rightleftharpoons KCl+[Fe(SCN)]Cl_2(blood-red)[/tex]

1. Color of ferric chloride solution is yellow. This is due to presence of ferric ions which have yellow color in their aqueous solutions.

2. KSCN has the colorless solution. This due to potassium ion forms colorless aqueous solution.

3. On mixing, KSCN with [tex]FeCl_3[/tex] we will get blood red color solution of [tex][FeSCN]Cl_2[/tex].

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The color of FeCl3 solution is yellow, the color of KX solution will be colorless while a mixture of the both will give a blood-red color.

Let the thiocyanate  ion be shown as X. Recall that Ions may posses different ions in solution. The color of an ion in solution is often unique and can be used to identify the ion in question. Now let us consider the following equilibrium; Fe3+(aq) (yellow) + X-(aq) (colorless) ⇄FeX2+(aq) (blood-red).

We can now see that the color of FeCl3 solution is yellow, the color of KX solution will be colorless while a mixture of the both will give a blood-red color.

Learn more about equilibrium: https://brainly.com/question/8139015

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