Answer : The percent composition of Na, O and H elements are 57.47%, 40% and 2.52% respectively.
Solution : Given,
Molar mass of sodium = 22.99 g/mole
Molar mass of oxygen = 16 g/mole
Molar mass of hydrogen = 1.008 g/mole
First we have to calculate the molar mass of NaOH.
[tex]\text{ Molar mass of NaOH}=\text{ Mass of Na}+\text{ Mass of O}+\text{ Mass of H}[/tex]
[tex]\text{ Molar mass of NaOH}=22.99+16+1.008=39.998g/mole[/tex]
Now we have to calculate the percent composition of all the elements.
[tex]\%\text{ composition of Na}=\frac{\text{ Molar mass of Na}}{\text{ Molar mass of NaOH}}\times 100=\frac{22.99}{39.998}\times 100=57.47\%[/tex]
[tex]\%\text{ composition of O}=\frac{\text{ Molar mass of O}}{\text{ Molar mass of NaOH}}\times 100=\frac{16}{39.998}\times 100=40\%[/tex]
[tex]\%\text{ composition of H}=\frac{\text{ Molar mass of H}}{\text{ Molar mass of NaOH}}\times 100=\frac{1.008}{39.998}\times 100=2.52\%[/tex]
Therefore, the percent composition of Na, O and H elements are 57.47%, 40% and 2.52% respectively.
