Respuesta :
Answer 1: The correct answer is option (B)
Answer 2: The correct answer is option (B)
Explanation 1:
[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]
moles of NaCl = [tex]\frac{\text{given mass of NaCl}}{\text{molar mass of NaCl}}=\frac{200 g}{58.5 g/mol}=3.4188 mol[/tex]
According to reaction, 2 moles NaCl are obtained from 2 moles of Na, then 3.4188 moles of NaCl are obtained from: [tex]\frac{1}{1}\times 3.4188[/tex] moles of Na.
Mass of Na = moles of sodium × Molar mass of sodium
[tex]=23 g/mol\times 3.4188 mol=78.632 g[/tex]
From the given option nearest answer to calculated answer is option (B) that is 78.65 g.
Explanation 2:
[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]
moles of potassium(K)= [tex]\frac{\text{given mass of K}}{\text{molar mass of K}}=\frac{23.5 g}{39 g/mol}=0.6025 mol[/tex]
According to reaction, 2 moles of K gives 2 moles of KOH , then 0.6025 moles of K will give : [tex]\frac{1}{1}\times 0.6025 moles[/tex] of KOH
Mass of KOH = moles of KOH × Molar mass of KOH
[tex]0.6025 mol\times 56 g/mol=33.74 g\approx 33.7 g[/tex]
From the given option nearest answer to calculated answer is option (A) that 33.7 g.
