Answer:
y-12= -3(x-6) (point slope form)
y = -3x + 30 ( slope intercept form)
Initial delivery time = 30 minutes
delivery time decreases 3 minutes per day
Step-by-step explanation:
To find equation of line we pick two points from the graph
(3,21) and (6,12)
Point slope form of a line is y-y1= m(x-x1)
m is the slope and (x1,y1) is the point on graph
Lets find out slope m
[tex]m=\frac{y_2-y_1}{x_2-x_1} =\frac{12-21}{6-3} =-3[/tex]
(x1,y1) is (6,12)
Point slope form of a line is y-y1= m(x-x1)
y-12= -3(x-6) (point slope form)
Now we solve for y to get slope intercept form
y-12 = -3x +18
Add 12 on both sides
y = -3x + 30 ( slope intercept form)
(b) To find initial time we plug in 0 for x
y = -3x + 30
y= -3(0) + 30
y=30
Initial delivery time = 30 minutes
Slope is the delivery time decreases per day
We got slope m = -3
So delivery time decreases 3 minutes per day
Answer:
well basically y-12= -3(x-6) (point slope form)
y = -3x + 30 ( slope intercept form)
Initial delivery time = 30 minutes
delivery time decreases 3 minutes per day
Step-by-step explanation:
To find equation of line we pick two points from the graph
(3,21) and (6,12)
Point slope form of a line is y-y1= m(x-x1)
m is the slope and (x1,y1) is the point on graph
Lets find out slope m
(x1,y1) is (6,12)
Point slope form of a line is y-y1= m(x-x1)
y-12= -3(x-6) (point slope form)
Now we solve for y to get slope intercept form
y-12 = -3x +18
Add 12 on both sides
y = -3x + 30 ( slope intercept form)
(b) To find initial time we plug in 0 for x
y = -3x + 30
y= -3(0) + 30
y=30
Initial delivery time = 30 minutes
Slope is the delivery time decreases per day
We got slope m = -3
So now we can say that the delivery time decreases 3 minutes per day! Hope this helps :)
Step-by-step explanation:
