Answer:
3 days
Step-by-step explanation:
Three hens lay 3 eggs in 3 days
We have to find the days in which 7 hens lay 7 eggs
Hen/egg=[tex]\frac{3}{3}[/tex]
Hen/egg=1
Using unitary method
1 hen lays 1 egg in 3 days
1 hen lays in 1 day =[tex]\frac{1}{3}[/tex]eggs
7 hens lay 7/3 eggs in 1 day
7 hens lay 1 egg=[tex]\frac{3}{7}[/tex]days
7 hens lay 7 eggs=[tex]\frac{3}{7}\times 7[/tex]
7 hens lay 7 eggs=3 days
Hence, 7 hens lay 7 eggs in 3 days
