jtorres0520
jtorres0520 jtorres0520
  • 13-12-2018
  • Mathematics
contestada

a) 1
b) -20
c) 20
d) 7

a 1 b 20 c 20 d 7 class=

Respuesta :

gmany
gmany gmany
  • 15-12-2018

[tex]f(x)=x^2;\ g(x)=x-3\\\\(g\ \circ\ f)(x)=(x^2)-4=x^2-3\\\\\text{Put x = -2 to the equation}\\\\(g\ \circ\ f)(-2)=(-2)^2-3=4-3=1\to\boxed{a)}[/tex]

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