Answer:
1526.0 cubic units
Step-by-step explanation:
Rotating rectangle AKLM you will get cylinder with height KA and base radius KL. From the given data
[tex]KA=\sqrt{(6-0)^2+(0-0)^2}=6,\\ \\KL=\sqrt{(0-0)^2+(9-0)^2}=9.[/tex]
The volume of the cylinder is
[tex]V_{cylinder}=\pi r^2\cdot H.[/tex]
Then
[tex]V_{cylinder}=\pi \cdot 9^2\cdot 6=486\pi \approx 1526.0\ un^3.[/tex]
