Answer:
[tex]x=-8[/tex]
Step-by-step explanation:
[tex]\mathrm{Expand\:}-4\left(2x+3\right):\quad -8x-12[/tex]
[tex]\mathrm{Expand\:}2x+6-\left(8x+2\right):\quad -6x+4[/tex][tex]-8x-12=-6x+4[/tex]
Add 12 to both sides:[tex]-8x-12+12=-6x+4+12[/tex]
→[tex]-8x=-6x+16[/tex]
Add 6x to both sides:[tex]-8x+6x=-6x+16+6x[/tex]
→[tex]-2x=16[/tex]
Divide both sides by -2:[tex]\frac{-2x}{-2}=\frac{16}{-2}[/tex]
Simplify.
Hope this helps!!
