The solutions to the inequality y ≤ 2x − 4 are shaded on the graph. Which point is a solution? (−1, 1) (1, −1) (3, 2) (2, 3)
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Answer:
(3,2)
Step-by-step explanation:
You can substitute or you can see which ordered pair is in the shaded area.
(-1,1):
y ≤ 2x - 4
1 ≤ 2(-1) - 4
1 ≤ -2 - 4
1 ≤ -6
(-1,1) is NOT a solution.
(1,-1):
y ≤ 2x - 4
-1 ≤ 2(1) - 4
-1 ≤ 2 - 4
-1 ≤ -2
(1,-1) is NOT a solution.
(3,2):
y ≤ 2x - 4
2 ≤ 2(3) - 4
2 ≤ 6 - 4
2 ≤ 2
(3,2) IS a solution.
(2,3):
y ≤ 2x - 4
3 ≤ 2(2) - 4
3 ≤ 4 - 4
3 ≤ 0
(2,3) is NOT a solution.
Solving linear equation mean calculating the unknown variable from the equation.
Let the linear equation : y = mx + c
If we draw the above equation on Cartesian Coordinates , it will be a straight line with :
m → gradient of the line
( 0 , c ) → y - intercept
Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :
[tex]\boxed {\large {m = \frac{y_2 - y_1}{x_2 - x_1}} }[/tex]
If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :
[tex]\boxed {y - y_1 = m ( x - x_1 )}[/tex]
Let us tackle the problem.
This probem is about Linear Inequality.
Given:
To determine which point is a solution , we could plot the points on the graph. The point that is in the shaded region will be the solution.
Let: point A (-1,1) , B (1,-1) , C (3,2) , D (2,3).
As shown in the graph in the attachment, from the four known points, only point C(3,2) is inside the shaded area.
∴ Point C is one of the solution of y ≤ 2x − 4
Grade: High School
Subject: Mathematics
Chapter: Linear Equations
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point