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José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be removed without the riders falling. When the ride accelerates to a speed of 17.0 m/s, his angular momentum is 3570 kg m2/s. What is his mass?

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits

Respuesta :

r = radius of the circle of the ride = 3.00 meters

v = linear speed of the person during the ride = 17.0 m/s

m = mass of the person in angular motion in the ride

L = angular momentum of the person in the ride = 3570 kg m²/s

Angular momentum is given as

L = m v r

inserting the values

3570 kg m²/s = m (17 m/s) (3.00 m)

m = 3570 kg m²/s/(51 m²/s)

m = 7 kg

hence the mass comes out to be 7 kg


Answer:

70.0 kg

Explanation:

L = mvr

You are solving for m so you change the equation to equal m

m = (L)/vr

m = (3570)/(17)(3)

m = 3570/51

m = 70

His mass is 70 kg.

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