Total money Marcus has = $28
Money spent to buy a notebook = $3.75
Money left now = [tex]28-3.75=24.25[/tex]
Money needed to be saved = $11.25
So, the amount of money Marcus can spend = [tex]24.25-11.25=13[/tex]
Cost of a packet of chips = $1.30
The inequality to determine the maximum number of chips he can buy is:
Let the number of chips Marcus can buy = x
As he cannot spend more than $13 to buy chips so equation becomes:
[tex]1.30x\leq 13[/tex]
Solving this we get
[tex]x\leq 10[/tex]
Hence, Marcus can buy a maximum of 10 packs of chips and save $11.25
