For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 18 N acts on a certain object, the acceleration of the object is 6 /ms2 . If the acceleration of the object becomes 5 /ms2 , what is the force?

Respuesta :

Answer: [tex]F=15N[/tex]


Step-by-step explanation:

1. You know that the force acting on the object varies directly with the object's acceleration. Then, by definition, you have:

[tex]F=ka[/tex]

Where [tex]F[/tex] is the force acting on the object, [tex]a[/tex] is the object's acceleration and [tex]k[/tex] is the constant of proportionality.

2. Keeping this on mind, you can calculate the constant of proportionality by substituting [tex]F=18[/tex] and [tex]a=6[/tex] into the equation and solving for [tex]k[/tex]:

[tex]18=k6\\k=\frac{18}{6}\\k=3[/tex]

3. Now, you can calculate the force when the acceleration of the object becomes 5 m/s², as following:

[tex]F=3(5)\\F=15[/tex]

3. The result is:

[tex]F=15N[/tex]

The acceleration that an objects gains is given by the mass of the object.

  • If the acceleration of the object becomes 5 m/s² the force is 15 N.

Reason:

The given parameters are;

The acting force ∝ The acceleration of the object.

The acceleration given by an amount of force, F, of 18 N = 6 m/s²

Required:

The force acting on the object acceleration, a, is 5 m/s².

Solution:

According to Newton's Second Law of motion, we have;

F = m·a

Where;

m = The mass of the object

Therefore, we have;

[tex]Mass, \, m = \dfrac{F}{a}[/tex]

From the conditions, F = 18 N, when a = 6 m/s², we have, the mass of the

given object is given as follows;

[tex]Mass \ of \ the \ object, \, m = \dfrac{18 \, N}{6 \ m/s^2} = 3 \, kg[/tex]

The force acting when the the acceleration, a = 5 m/s², is therefore;

F = 3 kg × 5 m/s² = 15 N

If the acceleration of the object becomes 5 m/s² the force is 15 N.

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