Respuesta :
Answer: [tex]F=15N[/tex]
Step-by-step explanation:
1. You know that the force acting on the object varies directly with the object's acceleration. Then, by definition, you have:
[tex]F=ka[/tex]
Where [tex]F[/tex] is the force acting on the object, [tex]a[/tex] is the object's acceleration and [tex]k[/tex] is the constant of proportionality.
2. Keeping this on mind, you can calculate the constant of proportionality by substituting [tex]F=18[/tex] and [tex]a=6[/tex] into the equation and solving for [tex]k[/tex]:
[tex]18=k6\\k=\frac{18}{6}\\k=3[/tex]
3. Now, you can calculate the force when the acceleration of the object becomes 5 m/s², as following:
[tex]F=3(5)\\F=15[/tex]
3. The result is:
[tex]F=15N[/tex]
The acceleration that an objects gains is given by the mass of the object.
- If the acceleration of the object becomes 5 m/s² the force is 15 N.
Reason:
The given parameters are;
The acting force ∝ The acceleration of the object.
The acceleration given by an amount of force, F, of 18 N = 6 m/s²
Required:
The force acting on the object acceleration, a, is 5 m/s².
Solution:
According to Newton's Second Law of motion, we have;
F = m·a
Where;
m = The mass of the object
Therefore, we have;
[tex]Mass, \, m = \dfrac{F}{a}[/tex]
From the conditions, F = 18 N, when a = 6 m/s², we have, the mass of the
given object is given as follows;
[tex]Mass \ of \ the \ object, \, m = \dfrac{18 \, N}{6 \ m/s^2} = 3 \, kg[/tex]
The force acting when the the acceleration, a = 5 m/s², is therefore;
F = 3 kg × 5 m/s² = 15 N
If the acceleration of the object becomes 5 m/s² the force is 15 N.
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