Parabola,Can someone please help me please ?

Answer:
a. opens: downward
b. vertex: (4, 2)
c. x-intercepts: (2, 0), (6, 0); y-intercept: (0, -6)
d. a.o.s.: x = 4
Step-by-step explanation:
Based on the picture the parabola opens downwards. Right away you know that the "a" value in the parabola's equation will be negative.
To find the coordinates of the vertex, you'll need to look at the picture. Remember: look on the x-axis first and then the y-axis next.
The very top of the parabola (maximum point = vertex) is at the x-value of 4 and the y-value of 2. This means the coordinates of the vertex of this parabola is (4, 2).
To find the x-intercepts, look at the x-axis and see where the parabola crosses it. The parabola goes through the x-axis at the x-values of 2 and 6, so the x-intercepts of this parabola are (2, 0) and (6, 0).
To find the y-intercept, look at the y-axis and see where the parabola crosses it. The parabola intersects the y-axis at the y-value of -6, so (0, -6) would be the y-intercept.
The equation for the axis of symmetry of a graph is always x = h, where h is the x-value of the coordinate of the vertex.
Since the vertex is (4, 2), where 4 = h, the equation of the axis of symmetry would be x = 4.