gustavoaldama10
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Let f(x)=−0.5(x−8)^2−2 .

What is the average rate of change for the quadratic function from x=−4 to x = 8?



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Please help, thank you

Respuesta :

Answer:

2

Step-by-step explanation:

[tex]f(x)=-0.5(x-8)^2-2[/tex]

Average rate of change formula is

[tex]Average = \frac{f(x_2)-f(x_1)}{x_2 - x_1}[/tex]

Here x1=-4  and x2= 8

Lets find f(x1)  and f(x2)

[tex]f(x)=-0.5(x-8)^2-2[/tex]

[tex]f(-4)=-0.5(-4-8)^2-2=-74[/tex]

[tex]f(8)=-0.5(8-8)^2-2=-2[/tex]

now we plug in all the values in the formula

[tex]Average = \frac{f(x_2)-f(x_1)}{x_2 - x_1}[/tex]

[tex]Average = \frac{-2-(-74)}{8-(-4)}[/tex]

[tex]Average = \frac{72}{12}=6[/tex]

Average rate of change = 6


marywdll

Answer:

Let f(x)=−0.5(x−8)2−2.

What is the average rate of change for the quadratic function from x=−4 to x = 8?

Enter your answer in the box.

Answer is 6 too the test

Step-by-step explanation:

Ver imagen marywdll

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