Answer: sqrt(19)/10
Step-by-step explanation:
sinx=0.9
x=arcsin(0.9)
Insert x for cos(x):
cos(arcsin(0.9)=
Use identify [tex]cos(arcsin(x))=\sqrt{1-x^{2} }[/tex], so
[tex]\sqrt{1-(\frac{9}{10})^{2}} =\sqrt{\frac{19}{100} } =\frac{\sqrt{19}}{10}[/tex]
Sorry if this is confusing.
