Answer:
D) Jumping with greater initial velocity would increase the height of his jump.
Explanation:
As the center of the team jumps, his motion is an accelerated motion with initial velocity [tex]v_0[/tex] upward and constant acceleration [tex]g=9.8 m/s^2[/tex] (acceleration due to gravity) towards the ground.
According to the law of conservation of energy, the gravitational potential energy of the center as it reaches its maximum height (h) is equal to the initial kinetic energy just after he starts the jump:
[tex]U=K\\mgh=\frac{1}{2}mv_0^2[/tex]
where
m is the mass of the center
g is the acceleration due to gravity
h is the maximum height
v0 is the initial velocity
Re-arranging the formula, we find:
[tex]h=\frac{v_0^2}{2g}[/tex]
Therefore, we see that the greater the initial velocity v0, the higher the center will jump.