1.A) 4.9 m
AL2006 Ace
The instant it was dropped, the ball had zero speed.
After falling for 1 second, its speed was 9.8 m/s straight down (gravity).
Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.
Falling for 1 second at an average speed of 4.9 m/s, is covered 4.9 meters.
ANYTHING you drop does that, if air resistance doesn't hold it back.
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2 idk sorry
1.
Answer: option A) 4.9 m
Explanation:
From the equation of motion,
s = u t + 0.5 a t ²
Where, t is the time, a is the acceleration, u is the initial velocity and s is the displacement.
Here, the initial velocity of the bowling ball is zero. u = 0
The ball falls under gravity. Thus, a = g = 9.8 m/s²
Time = 1.0 s
Hence, s = 0 + 0.5 × 9.8 m/s² × (1.0 s)² = 4.9 m
Thus, the ball has traveled 4.9 m after falling for 1.0 second. Correct option is A.
2.
Answer: option D) Jumping with greater initial velocity would increase the height of his jump
Explanation:
The maximum height achieved by a jumper depends on the angle , the initial velocity and acceleration due to gravity.
For maximum height, angle of the jump should be 90 degrees. Hence, more the initial velocity more the height of the jump.
Thus, correct option is D.
