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A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room? 2.19 L 3.33 L 3.68 L 5.60 L

Respuesta :

Answer:The answer is C on edge!

Explanation:

keilonmcalester

Answer:

C. 3.68

Explanation:

V1 / T1 = V2 / T2

3.50 / (25+273) = V2 / (40+273)

3.50(40+273) / (25+273) = V2

V2 = 3.676      3.676=3.68