Answer:
360 km/h
Explanation:
The truck left the diner at 1.00 pm and arrived at Jersey City at 2.00 pm - This means that the total time of the trip was 1 hour:
[tex]t = 1 h[/tex]
The distance covered between the diner and Jersey City was 360 km:
[tex]S=360 km[/tex]
So, the average speed of the truck is given by the distance covered divided by the time taken:
[tex]v=\frac{S}{t}=\frac{360 km}{1 h}=360 km/h[/tex]
Answer:
average speed of the truck will be 60 km/h
Explanation:
Truck started his Journey from diner at 1:00 PM
It reached to the Jersey City at 7:00 PM
so here we have total time interval of journey for the truck motion is given as
[tex]t = 7 - 1 = 6 hour[/tex]
total distance = 360 km
so here we know that average speed is defined as
[tex]v_{avg} = \frac{distance}{time}[/tex]
[tex]v_{avg} = \frac{360 km}{6 h}[/tex]
[tex]v_{avg} = 60 km/h[/tex]
so average speed of the truck will be 60 km/h
