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polynomial are given:P
[tex] p |x | = {x}^{3} - 3 {x}^{2} + 2x - 1[/tex]
show if
[tex]x = 1[/tex]
is the root of the polynomial.


Erpress the polynomial
[tex]p |x| [/tex]
in the tratment
[tex]p |x| = (x - 1)( {x}^{2} + ax + b) + c[/tex]

Respuesta :

Answer:

  • x = 1 is not a root
  • p(x) = (x -1)(x^2 -2x +0) -1

Step-by-step explanation:

a) p(1) = 1³ -3·1² +2·1 -1 = 1 -3 +2 -1 = -1 . . . . not zero

b) Dividing p(x) by x-1 gives x² -2x +0 with a remainder of -1 (as found in part (a)). So the function can be written as ...

... p(x) = (x -1)(x² -2x +0) -1

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Polynomial division can be done using synthetic division or long division. The latter can be done by hand or by using any of several on-line calculators. Attached is output from one of them.

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