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the gravitational force that earth exerts on the moon equals 2.03 x 10^20N. The moons mass is 7.35 x 10^22kg. What is the acceleration of the moon due to earth’s gravitational pull?

Respuesta :

AL2006

The first time we read this, we think that we'll have to go look up a bunch of stuff about the gravitational constant, centripetal force, orbital mechanics, the Moon's period of revolution, and who knows whut owl !

But you know whut ?  The only thing we need is Newton's 2nd law:

F = m A

Divide each side by m :

Acceleration = Force / mass

Acceleration = (2.03 x 10²⁰ Newtons) / (7.35 x 10²² kg)

Acceleration = (2.03 x 10²⁰ / 7.35 x 10²² kg) (m/s²)

Acceleration = 0.00276 m/s²


Lanuel

The acceleration of the Moon due to Earth’s gravitational pull, is [tex]2.76[/tex] × [tex]10^{-3} \; m/s^2[/tex].

Given the following data:

  • Gravitational force = [tex]2.03[/tex] × [tex]10^{20} N[/tex]
  • Mass of Moon = [tex]7.35[/tex] × [tex]10^{22} Kg[/tex]

To find the acceleration of the Moon due to Earth’s gravitational pull, we would use Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by the formula;

[tex]Acceleration = \frac{Force}{Mass}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Acceleration = \frac{2.03(10^{20})}{7.35(10^{22})}[/tex]

Acceleration = [tex]2.76[/tex] × [tex]10^{-3} \; m/s^2[/tex]

Therefore, the acceleration of the Moon due to Earth’s gravitational pull, is [tex]2.76[/tex] × [tex]10^{-3} \; m/s^2[/tex].

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