Answer:
Hang time of the basketball player is 0.83 sec.
Step-by-step explanation:
A pro basketball player has a vertical leap of 33 in.
His hang-time can be calculated by the function given by,
[tex]V=48t^2[/tex]
Where,
V = vertical leap (vertical leap is the act of raising itself in the vertical plane)
t = the time for which the object stays in the air
Putting all the values,
[tex]\Rightarrow 33=48t^2[/tex]
[tex]\Rightarrow t^2=\dfrac{33}{48}[/tex]
[tex]\Rightarrow t=\sqrt{\dfrac{33}{48}}[/tex]
[tex]\Rightarrow t=0.83\ sec[/tex]
Therefore, hang time of the basketball player is 0.83 sec.
