Enzo156
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A ball is thrown into the air from a height of 6 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 95t + 6, where t is measured in seconds and h is the height in feet. What is the height of the ball after 2 seconds? What is the maximum height of the ball? When will the ball hit the ground? What domain makes sense for the function? You must show your work on parts a-c to receive credit.

Respuesta :

Answer:

the height of the ball after 2 seconds is 132 feet

Maximum height of the ball is 147.016 feet

domain is t>=0

Step-by-step explanation:

The function that models this situation is [tex]h(t) = -16t^2 + 95t + 6[/tex]

To find  the height of the ball after 2 seconds, we plug in 2 for t

[tex]h(2) = -16(2)^2 + 95(2) + 6=132[/tex]

the height of the ball after 2 seconds is 132 feet

To find maximum height we find out vertex

We apply formula x=-b/2a

a=-16 , b= 95

[tex]x=\frac{-b}{2a} =\frac{-95}{2(-16)}=2.969[/tex]

now we plug in 2.969 and find out y

[tex]h=-16(2.969)^2 + 95(2.969) + 6=147.016[/tex]

Maximum height of the ball is 147.016 feet

Domain is the set of 't' values for which function is defined

Time 't' cannot be negative so t is all positive real number

domain is t>=0