This is a very difficult question. In △PQR, point T is on side QR such that QT=6 and TR=10. What is the ratio of the area of △PQT to the area of △PTR. Help please
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Answer:
the ratio of the area is 3:5
Step-by-step explanation:
Find a common factor of 6 and 10 and then divide it, the common factor is 2
6 divided by 2 is 3
10 divided by 2 is 5
so your ratio area is 3:5
Hope this helps :)