Step-by-step explanation:
Since PQRS is a rectangle ,
The x- coordinate for S and R is same . The x coordinate of S is 2x
So R is (2x, 2y)
Mid point of 2x is x and mid point of 2y is y
Diagonals of a rectangle bisect each other so coordinate of T are (x,y)
In triangle PTQ, the length of the base is 2y and height is x
We know area of triangle is [tex]\frac{1}{2}* base * height[/tex]
[tex]\frac{1}{2}* 2y * x[/tex]= xy
Area of the triangle PTQ is xy
In triangle RTQ, the length of the base is 2x and height is y
area of triangle is [tex]\frac{1}{2}* base * height[/tex]
[tex]\frac{1}{2}* 2x * y[/tex]= xy
In triangle RTS, the length of the base is 2y and height is x
We know area of triangle is [tex]\frac{1}{2}* base * height[/tex]
[tex]\frac{1}{2}* 2y * x[/tex]= xy
