Answer:
A
Step-by-step explanation:
Your first step is to figure out what f(x) is. You should start with x = 0. f(x) has a value of - 4. That only tells you that whatever x is or what it is coupled with, the constant term is - 4.
What you know so far is that y = x something - 4
Now go to work on some of the other numbers. It really doesn't look linear so don't try it.
What happens when x = 16? Somehow f(x) winds up being 0. What can cause that?
First of all it can't be y = ax - 4. We've already establish the constant must be - 4
What about y = ax^2 - 4
That cannot be either. y = 16^2*a - 4 ?? y = 256ax - 4. No other value will fit the bill.
By looking at g(x) you get the idea that y = a*sqrt(x) - 4 might have something to do with f(x). The most obvious value for a = 1, so try it first.
- y = sqrt(x) - 4
- y = sqrt(16) - 4
- y = 4 - 4 = 0
- Looking good!!
Now try some of the other values.
- x = 9
- y = sqrt(9) - 4
- y = 3 - 4
- y = -1
And that's what the table says.
The red graph is y = sqrt(x) - 4
The blue graph is y = 4*sqrt(x) - 8
Answer
It looks like A is the answer.
g(x) has a y intercept of - 8
f(x) has a y intercept of - 4
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The two intercepts are not equal. If they were they would start from the same point. B is incorrect
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C is wrong. the x intercepts are distinct points. One is 4 and the other is 16 I think.
0 = sqrt(x) - 4
4 = sqrt(x) Square both sides.
16 = x This is the x intercept of the red line
The other intercept = 4 (Blue line). I'll leave you to work it out. Leave a not if you can't.
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A and D can't both be true. Since A is true, D can't be.
