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A 5.0 kilogram rock rolls off the edge of a cliff. If it is traveling at a speed of 24.2m/s when it hits the ground, what is the height of the cliff?

Respuesta :

Using the kinematic equation ;

vf²=vi²+2ad just rearrange for d;

vf²-vi²=2ad;

(vf²-vi²)/2a=d

Now plug the numbers in.

vf=24.2

vi=0

a=9.81=g


(24.2²-0²)/(2*9.81)=29.8 m.



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