BRAINLIESSSSTT!!! ASAP!!!
Rectangle BCDE is shown on the coordinate grid. Rectangle BCDE is dilated with the origin as the center of dilation using the rule (x, y) → (13x, 13y) to create rectangle B'C'D'E'.

Which statement is true?

A. Rectangle B'C'D'E' is larger than rectangle BCDE, because the scale factor is greater than 1.

B. Rectangle B'C'D'E' is smaller than rectangle BCDE, because the scale factor is less than 1.

C. Rectangle B'C'D'E' is smaller than rectangle BCDE, because the scale factor is greater than 1.

D. Rectangle B'C'D'E' is larger than rectangle BCDE, because the scale factor is less than 1.

- Correctly answer and Thankyou


BRAINLIESSSSTT ASAPRectangle BCDE is shown on the coordinate grid Rectangle BCDE is dilated with the origin as the center of dilation using the rule x y 13x 13y class=

Respuesta :

I'm pretty sure it's B
let me know if I'm right plz
Good luck

Answer:  The correct option is

(A) Rectangle B'C'D'E' is larger than rectangle BCDE, because the scale factor is greater than 1.

Step-by-step explanation:  Given that the rectangle BCDE is shown on the coordinate grid. Rectangle BCDE is dilated with the origin as the center of dilation using the following rule to create rectangle B'C'D'E' :

[tex](x,y)~~~\Rightarrow~~~(13x,13y).[/tex]

We are to select the true statement.

We know that

if a polygon with one vertex (a, b) is dilated using the scale factor s, then the corresponding vertex of the dilated polygon is (sa, sb).

Also, if s < 1, then the dilated figure is smaller then the original one.

And, if s > 1, then the dilated figure is larger than the original one.

Now, in the given situation. the rectangle BCDE is dilated using the rule [tex](x,y)~~~\Rightarrow~~~(13x,13y).[/tex] to form rectangle B'C'D'E.

So, the scale factor of dilation is given by

[tex]s=13>1.[/tex]

Therefore, the rectangle B'C'D'E is larger than rectangle BCDE, because the scale factor is greater than 1.

Option (A) is CORRECT.