Answer:
8 , 20, 50, 125, 625/2 option D
Step-by-step explanation:
Given that,
first term a₁ = 8
common ratio (r) = [tex]\frac{5}{2}[/tex]
We need to find the five terms of the geometric progression
We know that the nth term formula :
aₙ = a₁rⁿ-¹
where a₁ is first term and r is the common ratio
n is the number of terms
Second term (n=2)
a₂ = 8*[tex](\frac{5}{2} )^{2-1}[/tex] = [tex]\frac{8*5}{2}[/tex] = 20
Third term (n = 3)
a₃ = 8*[tex](\frac{5}{2} )^{3-1} = 8*(\frac{5}{2} )^{2} = (\frac{8*25}{4} ) = 50[/tex]
Forth term (n=4)
a₄ = [tex]8(\frac{5}{2} )^{4-1} = 8*(\frac{5}{2} )^{3} = (\frac{8*125}{8} ) = 125[/tex]
Fifth term (n=5)
a₅ = [tex]8(\frac{5}{2} )^{5-1} = 8*(\frac{5}{2} )^{4} = (\frac{8*625}{16} ) = \frac{625}{2}[/tex]
So, five terms are :
8 , 20, 50, 125, 625/2
