Hello from MrBillDoesMath!
Answer:
All real x
Discussion:
Take any real number, say, P. Then solve
f(x) = (x-2)2 + 2 = P => (subtract 2 from both sides)
(x-2)2 = P -2 => (divide both sides by 2)
(x-2) = (1/2) (P-2) => (add 2 to both sides)
x = (1/2)(P-2) + 2
Conclusion: for any real number range value, P, there is an x (given by the above formula) such that f(x) = P. In other words, the range of f is all real numbers x
Regards,
MrB
