Frank invests $1,000 in simple interest investment account that pays 8% a year. After a number of years, he withdraws his balance of $2,200. Using the formula l=prt, how many years was his money invested? 2.75 years 10 years 15 years 27.5 years

Respuesta :

Answer:

[tex]15\ years[/tex]

Step-by-step explanation:

we know that

The simple interest formula is equal to

[tex]I=P(rt)[/tex]

where

A is the Final Investment Value

I is the amount of money in Interest  

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

[tex]t=?\ years\\ P=\$1,000\\ A=\$2,200\\r=0.08[/tex]

Find the interest I

[tex]I=A-P=\$2,200-\$1,000=\$1,200[/tex]

substitute in the formula above

[tex]\$1,200=\$1,000(0.08t)[/tex]

Solve for t

[tex]t=1.2/0.08=15\ years[/tex]

Answer:

15

Step-by-step explanation: