Answer:
The coordinates of image are X'(-3,4), Y'(-5,0) and Z'(-1,1).
Step-by-step explanation:
The vertices of triangle XYZ are X(-2,1), Y(-4,-3) and Z(0,-2).
It is given that the triangle translated by rule
[tex](x,y)\rightarrow (x-1,y+3)[/tex]
The coordinates of image of XYZ are
[tex]X(-2,1)\rightarrow X'(-2-1,1+3)[/tex]
[tex]X(-2,1)\rightarrow X'(-3,4)[/tex]
[tex]Y(-4,-3)\rightarrow Y'(-4-1,-3+3)[/tex]
[tex]Y(-4,-3)\rightarrow Y'(-5,0)[/tex]
[tex]Z(0,-2)\rightarrow Z'(0-1,-2+3)[/tex]
[tex]Z(0,-2)\rightarrow Z'(-1,1)[/tex]
Therefore coordinates of image are X'(-3,4), Y'(-5,0) and Z'(-1,1).
