Answer:
2 [tex]\frac{11}{20}[/tex]
Step-by-step explanation:
one way is to change the mixed numbers to improper fractions
5 [tex]\frac{1}{4}[/tex] = [tex]\frac{21}{4}[/tex] and 2 [tex]\frac{7}{10}[/tex] = [tex]\frac{27}{10}[/tex]
now we have
[tex]\frac{21}{4}[/tex] - [tex]\frac{27}{10}[/tex]
We require the fractions to have a common denominator before we can subtract them.
the lowest common multiple of 4 and 10 is 20
multiply the numerator/denominator of the first fraction by 5 and the numerator/denominator of the second fraction by 2
= [tex]\frac{21(5)}{4(5)}[/tex] - [tex]\frac{27(2)}{10(2)}[/tex]
= [tex]\frac{105}{20}[/tex] - [tex]\frac{54}{20}[/tex]
now subtract the numerators leaving the denominator
= [tex]\frac{51}{20}[/tex] = 2 [tex]\frac{11}{20}[/tex] ← in simplest form
Answer:
[tex]\frac{102}{40} = \frac{51}{20}[/tex]
Step-by-step explanation:
[tex]5\frac{1}{4} - 2\frac{7}{10} =[/tex]
simplify
[tex]\frac{21}{4} - \frac{27}{10} =[/tex]
common denominator
[tex]\frac{210}{40} - \frac{108}{40} = \frac{102}{40}[/tex]
simplify
[tex]\frac{102}{40} = \frac{51}{20}[/tex]
